Odpowiedź:
1)
(x³ - 4)(x² - 9)(x² + 7) = 0
x³ - 4 = 0 v x² - 9 = 0 v x² + 7 = 0
x³ = 4 v x² = 9 v x² = - 7
[tex]x = \sqrt[3]{4}[/tex] v x = 3 v x = -3
x ∈ {-3, [tex]\sqrt[3]{4}[/tex], 3}
2)
(x² - 4)(x - 2)(x + 3)(x² - 5) = 0
x² - 4 = 0 v x - 2 = 0 v x + 3 = 0 v x² - 5 = 0
x² = 4 v x = 0 v x = - 3 v x² = 5
x = 2 v x = - 2 v x = 0 v x = - 3 v [tex]x = \sqrt{5}[/tex]
x ∈ {-3, -2, 0, 2, [tex]\sqrt{5}[/tex]}
