Prosze o pomoc i rozwiazania daje 100pkt

Prosze O Pomoc I Rozwiazania Daje 100pkt class=

Odpowiedź :

1. [tex]\frac{\sqrt[5]{64} }{\sqrt[5]{2} } -\sqrt[3]{5} *\sqrt[3]{25} = \sqrt[5]{64:2}-\sqrt[3]{5*25} =\sqrt[5]{32} -\sqrt[3]{125} = 2 - 5 = -3[/tex]

Odp: B

2. 100% - 17% = 83%

83%x = 1577

0,83x = 1577 /:0,83

x = 1900

Odp:C

3. ㏒(1/3)6 + ㏒(1/3)9 - ㏒(1/3)2 = ㏒(1/3)(6*9) -㏒(1/3)2 = ㏒(1/3)54 - ㏒(1/3)2 = ㏒(1/3)(54:2) = ㏒(1/3)27 = log(3^-1)3^3 = 3/-1 = -3

Odp: A

4. [tex]\frac{3^{4}*3^{8} }{9^{4} } = \frac{3^{4+8} }{(3^{2})^{4} } =\frac{3^{12} }{3^{2*4} } =\frac{3^{12} }{3^{8} } = 3^{12-8} =3^{4} = (3^{2}) ^{2} =9^{2}[/tex]

Odp: C

5. x² + 2x ≤ 0

x( x + 2) ≤ 0

x = 0 v x = -2

x należy  do <-2, 0>

Odp: D