Odpowiedź:
[tex]a)\ \ -3\cdot4\cdot(-3\frac{1}{4})\cdot(-3)=-\not12^3\cdot(-\frac{13}{\not4_{1}})\cdot(-3)=3\cdot13\cdot(-3)=39\cdot(-3)=-117\\\\\\b)\ \ -2,8a\cdot40ax\cdot(-1)\cdot a^2=2,8a\cdot40ax\cdot a^2=112a^4x\\\\\\c)\ \ (-6y)\cdot(-y)\cdot(-0,2)\cdot y=-1,2y^3\\\\\\d)\ \ (2\frac{1}{2})\cdot x\cdot(-1\frac{4}{5})\cdot(-10)xy=\frac{\not5^1}{2}x\cdot(-\frac{9}{\not5_{1}})\cdot(-10)xy=-\frac{9}{\not2_{1}}x\cdot(-\not10^5)xy=\\\\=-9x\cdot(-5)xy=45x^2y[/tex]
[tex]e)\ \ -4\cdot(-x)\cdot(-y)\cdot(-y)\cdot x\cdot y^2=4xy^2\cdot x\cdot y^2=4x^2y^4\\\\\\f)\ \ \frac{1}{3}\cdot a\cdot a\cdot(-b)\cdot a\cdot(-b)\cdot\frac{1}{3}=\frac{1}{3}a^3b^2\cdot\frac{1}{3}=\frac{1}{9}a^3b^2[/tex]
