Odpowiedź :
a)
[tex]a \sqrt{2} = 3 \sqrt{2} [/tex]
Z tw. Pitagorasa
[tex](3 \sqrt{2} {)}^{2} + (3 \sqrt{2} {)}^{2} = {x}^{2} \\ 9 \times 2 + 9 \times 2 = {x}^{2} \\ 18 + 18 = {x}^{2} \\ {x}^{2} = 36 \\ \underline{x = 6}[/tex]
b)
[tex]a = 4 \sqrt{3} [/tex]
[tex]H = 4 \sqrt{3} \times \sqrt{3} = 4 \sqrt{9} = 4 \times 3 = 12[/tex]
Z tw. Pitagorasa
[tex](4 \sqrt{3} {)}^{2} + {12}^{2} = {x}^{2} \\ 16 \times 3 + 144 = {x}^{2} \\ 48 + 144 = {x}^{2} \\ {x}^{2} = 192 \\ x = \sqrt{192} \\ x = \sqrt{64 \times 3} \\ \underline{x = 8 \sqrt{3} }[/tex]