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DAJE NAJJJJJJ. Blagam​

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Odpowiedź :

Metix325viz

Odpowiedź:

[tex]\left \{ {{x+6=3x+y} \atop {4=x-2y+5}} \right. \\\left \{ {{-2x-y=-6} \atop {-x+2y=1}} \right. \\\left \{ {{-2x-y=-6} \atop {2x-4y=-2}} \right. \\-5y=-8\\y=\frac{8}{5} =1\frac{3}{5} \\[/tex]

[tex]x+6=3x+\frac{8}{5} \\2x=6-1\frac{3}{5}\\2x=4\frac{2}{5} \\x=\frac{22}{5} *\frac{1}{2} =\frac{11}{5} =2\frac{1}{5}[/tex]

[tex]\left \{ {{x=2\frac{1}{5} } \atop {y=1\frac{3}{5} }} \right.[/tex]

Basetlaviz

[tex]x+6 = 3x+y\\4 = x-2y+5\\\\x-3x-y = -6\\x-2y=4-5\\\\-2x-y=-6 \ \ |\cdot(-2)\\x-2y = -1\\\\4x+2y = 12\\x-2y = -1\\------- \ \ \ + \ \ (dodajemy \ obustronnie)\\5x = 11 \ \ /:5\\\\\underline{x = \frac{11}{5} = 2\frac{1}{5}}\\\\y = -2x+6 = -2\cdot\frac{11}{5}+6 = -\frac{22}{5}+\frac{30}{5}\\\\\underline{y = \frac{8}{5} = 1\frac{3}{5}}[/tex]

[tex]\{x = 2\frac{1}{5}\\\\\{y = 1\frac{3}{5}[/tex]

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