Odpowiedź:
[tex]log_2(x+1)=4\\log_2(x+1)=4 ,x > -1\\x+1=2^4\\x+1=16\\x=16-1\\x=15, x > -1\\\\x=15\\\\\\log_4(5x-9)=2\\log_4(5x-9)=2, x > \frac{9}{5}\\5x-9=4^2\\ 5x-9=16\\5x=16+9\\5x=25\\x=5, x > \frac{9}{5}\\ \\x=5\\\\\\log\frac{1}{3} (1-2x)=-2\\1-2x=(\frac{1}{3})^{-2}\\ 1-2x=3^2\\ 1-2x=9\\-2x=9-1\\-2x=8\\\\x=-4\\\\\\log_3(2x+5)=3\\2x+5=3^3\\2x+5=27\\2x=27-5\\2x=22\\\\x=11\\\\\\log_5(5x-9)=2\\5x-9=5^2\\5x-9=25\\5x=25+9\\5x=34\\[/tex]
[tex]x=\frac{34}{5}[/tex]
[tex]log_5(2x-7)=2\\2x-7=5^2\\2x-7=25\\2x=25+7\\2x=32\\\\x=16[/tex]
