Odpowiedź:
[tex]1. \\\\(x^3+27)(x^2+2x-3)=0\\x^3+27=0\\x^2+2x-3=0\\\\x=-3\\x=1\\x=-3\\\\x_1=-3\\x_2=1\\\\\\2.\\\\-3x^3+3x+36\geq 0\\-x^2+x+12\geq 0\\-x^2+4x-3x+12\geq 0\\-x*(x-4)-3(x-4)\geq 0\\(-x-3)*(x-4)\geq 0\\\\\\\left \{ {{-x-3\geq 0} \atop {x-4\geq 0}} \right. \\\\\left \{ {{-x-3\leq 0} \atop {x-4\leq 0}} \right. \\\\\\x=[-3,4]\\\\\\3.\\\\P=\frac{1}{2} (a+b)*h\\\\P=\frac{1}{2}(6+10)*12\\\\P=\frac{1}{2}*16*12\\\\\\P=96[/tex]
