Witaj :)
a]
[tex]\sqrt{\frac{36}{49}}\cdot(\sqrt{121}+\sqrt9)=\sqrt{(\frac{6}{7})^2}\cdot(\sqrt{11^2}+\sqrt{3^2})=\frac{6}{7}\cdot(11+3)=\frac{6}{7}\cdot14=6\cdot2=\boxed{12}\\[/tex]
b]
[tex]\sqrt{1,44}+\sqrt{0,04}-\sqrt[3]{0,008}=\sqrt{1,2^2}+\sqrt{0,2^2}-\sqrt[3]{0,2^3}=1,2+0,2-0,2=\boxed{1,2}\\[/tex]
