[tex]\frac{ 6x^2(2x^4y^3)^3 }{24(x^5y)^2xy^6} =\frac{ 6x^2 *2^3*x^ {12}*y^9 }{24 x^ {10}*y^2*xy^6} = \frac{ 6x^2 *8*x^ {12}*y^9 }{24 x^ {10}*y^2*xy^6} = \frac{ \not{48}^2x^{2+12} *y^9 }{\not{24}^1 x^{10+1}*y^{2+6} } =\\\\=\frac{ 2x^{14} *y^9 }{ x^{11}*y^{8} } = 2 x^{14-11}*y^{9-8} =2x^3y \\\\\\x=3,\ \ y=250 \\\\2x^3y=2*3^3*250=2*27*250=54*250=13\ 500[/tex]
[tex]odp.\ Wartosc\ wyrazenia\ wynosi \ 13\ 500.[/tex]
