[tex]3 \sqrt[3]{128} + 4 \sqrt[3]{54} - \sqrt[3]{250} = \\ = 3 \sqrt[3]{64 \times 2} + 4 \sqrt[3]{27 \times 2} - \sqrt[3]{125 \times 2} = \\ = 3 \times 4 \sqrt[3]{2} + 4 \times 3 \sqrt[3]{2} - 5 \sqrt[3]{2} = \\ = 12 \sqrt[3]{2} + 12 \sqrt[3]{2} - 5 \sqrt[3]{2} = \\ = 24 \sqrt[3]{2} - 5 \sqrt[3]{2} = \\ = \boxed{19 \sqrt[3]{2} }[/tex]
Odpowiedź:
3∛128 + 4∛54 - ∛250 = 3∛(2*64) + 4∛(2*27)- ∛(2*125) =
= 3*4∛2 + 4*3∛2 - 5∛2 = 12∛2 + 12∛2 - 5∛2 = 24∛2 - 5∛2 = 19∛2
Szczegółowe wyjaśnienie:
