Odpowiedź:
Szczegółowe wyjaśnienie:
III.
[tex]-3a^2+2a(a-4)=-3a^2+2a^2-8a=-a^2-8a\\\\a(3-a)-2,75(4a-3)-8\frac{1}{4}=3a-a^2-11a-8,25-8,25=-a^2-8a-16,5\\\\(3a^2-4ab)*(-5)-4b(2a-ab)-2a(4-7a+6b+2b^2)=-15a^2+20ab-8ab+4ab^2-8a+14a^2-12ab-4ab^2=-a^2-8a[/tex]
IV.
[tex]p(4p-5s)-s(-5p+2s)=4p^2-5ps+5ps-2s^2=4p^2-2s^2\\\\2p(2p-s)-s(p-s)*(-2)=4p^2-2ps+2ps-2s^2=4p^2-2s^2\\\\\frac{2}{3}p(6p-2s+4)-\frac{1}{6}s(1+12s-8p)-\frac{1}{3}(8p-\frac{1}{2}s)=4p^2-\frac{4}{3}ps+\frac{8}{3}p-\frac{1}{6}s-2s^2+\frac{4}{3}ps-\frac{8}{3}p+\frac{1}{6}s=4p^2-2s^2[/tex]