Odpowiedź :
a) [tex]\frac{1}{3}x - 2 = x +2[/tex] /*3
x - 6 = 3x + 6
x - 3x = 6 +6
-2x = 12 /: (-2)
x = -6
b) [tex]1 - \frac{6}{7}x = \frac{4}{7}[/tex] /*7
7 - 6x = 4
-6x = 4 - 7
-6x = -3 /:(-6)
x = [tex]\frac{3}{6}[/tex]
x = [tex]\frac{1}{2}[/tex]
c) [tex]6(\frac{1}{4}x - 2) = 18[/tex] /*6
[tex]\frac{1}{4}x - 2 = 3[/tex] /*4
x - 8 = 12
x = 12 + 8
x = 20
d) [tex]\frac{x}{6} - \frac{1}{6} = 1[/tex] /*6
x - 1 = 6
x = 6 + 1
x = 7
e) [tex]-2(2x - 1) = \frac{x}{3}[/tex]
-4x + 2 = [tex]\frac{x}{3}[/tex] /*3
-12x + 6 = x
-12x - x = -6
-13x = -6
x = [tex]-\frac{6}{13}[/tex]
f) [tex]\frac{2}{5}(3-x) = -2[/tex] /*[tex]\frac{5}{2}[/tex]
3 - x = -5
-x = -5 - 3
-x = -8
x = 8
g) [tex]\frac{3}{4} (2-3x) = -6[/tex] /*[tex]\frac{4}{3}[/tex]
2-3x = -8
-3x = -8 - 2
-3x = -10 /:(-3)
x = [tex]\frac{10}{3}[/tex]
x = [tex]3\frac{1}{3}[/tex]
h) [tex]\frac{1}{5}(x-3) = 9-x\\[/tex] /*5
x - 3 = 45 - 5x
x + 5x = 45 + 3
6x = 48 /:6
x = 8
i) [tex]\frac{0,6+x}{2} = x + 1[/tex]
[tex]\frac{\frac{3}{5}+x }{2} = x +1[/tex]
[tex]\frac{\frac{3+5x}{5}+x }{2} = x + 1[/tex]
[tex]\frac{3+5x}{10} = x + 1[/tex] /*10
3+5x = 10x + 10
5x - 10x = 10 - 3
-5x = 7 /:(-5)
x = [tex]-\frac{7}{5}[/tex]
x = [tex]-1\frac{2}{5}[/tex]