[tex]\left \{ {{x(1-2x)-y(1-y)=(y-\sqrt2x)(y+\sqrt2x)+3} \atop {2x-(2y-\frac{1}{4})^2+16\frac{1}{16}=(2y+3)(3-2y)}} \right. \\\\\left \{ {{x-2x^2-y+y^2=y^2-2x^2+3} \atop {2x-(4y^2-y+\frac{1}{16})+16\frac{1}{16}=9-4y^2} \right. \\\\\left \{ {{x-y=3} \atop {2x-4y^2+y-\frac{1}{16}+16\frac{1}{16}=9-4y^2} \right. \\\\\left \{ {{x-y=3} \atop {2x+y+16=9} \right. \\\\\left \{ {{x-y=3} \atop {2x+y=-7} \right|+\\\\\left \{ {{3x=-4\ |:3} \atop {2x+y=-7} \right.\\\\[/tex]
[tex]\left \{ {{x=-\frac{4}{3}} \atop {2*(-\frac{4}{3})+y=-7} \right.\\\\\left \{ {{x=-1\frac{1}{3}} \atop {-\frac{8}{3}+y=-7} \right.\\\\\left \{ {{x=-1\frac{1}{3}} \atop {y=-7+2\frac{2}{3}} \right.\\\\\left \{ {{x=-1\frac{1}{3}} \atop {y=-4\frac{1}{3}} \right.[/tex]
