Rozwiązane

Potęgowanie iloczynu:
Przykład: (-9w)²= (-9)²*w²=81w²
(3y)²
(-2x)³=
(abc)³=
-(3x)²=
-(2y)³=
2³*5³=

Odpowiedź :

Rajsus16aviz

[tex](3y)^{2} = 3^{2}* y^{2} = 9y^{2} \\(-2x)^{3} = (-2)^{3} *x^{3}=-8x^{3} \\(abc)^{3} = a^{3} *b^{3} *c^{3} = a^{3} b^{3} c^{3}\\-(3x)^{2} = -(3^{2} )*x^{2} =-9x^{2} \\-(2y)^{3} = -(2^{3} )*y^{2} =-8y^{2} \\2^{3} *5^{3} =8*125=1000[/tex]

Basetlaviz

[tex](3y)^{2} = 3^{2}\cdot y^{2} = 9y^{2}\\\\(-2x)^{3} = (-2)^{3}\cdot x^{3} = -8x^{3}\\\\(abc)^{3} =a^{3}\cdot b^{3}\cdot c^{3} = a^{3}b^{3}c^{3}\\\\-(3x)^{2} = -(3^{2}\cdot x^{2}) = -(9x^{2}) = -9x^{2}\\\\-(2y^{3}) = -(2^{3}\cdot y^{3}) = -(8y^{3}) = -8y^{3}\\\\2^{3}\cdot5^{3} = (2\cdot5)^3} = 10^{3} = 1000[/tex]

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