Odpowiedź:
Zadanie 6 na zdjęciu.
5.
[tex] ({ \frac{2}{3} })^{5} \times ( { \frac{2}{3} })^{5} = ( { \frac{2}{3} })^{10} [/tex]
[tex]( { - 6})^{15} \div ( { - 6})^{3} = ( { - 6})^{12} = {6}^{12} [/tex]
[tex]( {1.2})^{14} \div ( {1.2})^{10} = ( {1.2})^{4} [/tex]
[tex] {( {5}^{3} })^{2} = {5}^{6} [/tex]
[tex] \frac{ {( \sqrt{3}) }^{6} \times {3}^{7} }{ {3}^{13} \div {3}^{3} } = \frac{( { {3}^{ \frac{1}{2} } )}^{6} \times {3}^{7} }{ {3}^{10} } = \frac{ {3}^{3} \times {3}^{7} }{ {3}^{10} } = \frac{ {3}^{10} }{ {3}^{10} } = {3}^{0} [/tex]
[tex] \frac{( { \sqrt{5} )}^{16} \times ( { \sqrt[3]{5} )}^{9} }{( { {5}^{5} })^{2} } = \frac{ {5}^{8} \times {5}^{3} }{ {5}^{10} } = \frac{ {5}^{11} }{ {5}^{10} } = {5}^{1} [/tex]
