Odpowiedź:
Korzystamy z tw Pitagorasa
[tex] {c}^{2} = {a}^{2} + {b}^{2} [/tex]
a)
[tex]c = \sqrt{9 + 16} = 5[/tex]
b)
[tex]c = \sqrt{1 + 9} = \sqrt{10} [/tex]
C)
[tex]c = \sqrt{64 + 36} = 10[/tex]
d)
[tex]c = \sqrt{9 + 9} = 3 \sqrt{2} [/tex]
e)
[tex]c = \sqrt{144 + 25} = 13 [/tex]
