[tex]Dane:\\m = 500 \ g = 0,5 \ kg\\a = 3\frac{m}{s^{2}}\\Szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki:\\\\a = \frac{F_{w}}{m} \ \rightarrow \ \ F_{w} = m\cdot a\\\\F_{w} = 0,5 \ kg\cdot3\frac{m}{s^{2}}\\\\\boxed{F_{w} = 1,5 \ N}[/tex]
