Odpowiedź :
[tex]4(2x+3y)-6(5xy-2x) = 8x+12y-30xy+12x=20x+12y-30xy\\\\dla \ \ x = 3 \ i \ y = -2\\\\20x+12y-30xy = 20\cdot3+12\cdot(-2) -30\cdot3\cdot(-2) = 60-24+180 = \boxed{216}[/tex]
[tex]Lub\\\\dla \ \ x = 3 \ i \ y = -2\\\\4(2x+3y)-6(5xy-2x) = 4[2\cdot3+3\cdot(-2)] -6[5\cdot3\cdot(-2)-2\cdot3] =\\\\=4(6-6)-6(-30-6) = 0-6\cdot(-36) = \boxed{216}[/tex]
[tex]x = 3 \\ y = - 2[/tex]
[tex]4(2x + 3y) - 6(5xy - 2x) = \\ = 8x + 12y - 30xy + 12x = \\ =20x + 12y - 30xy = \\ = 20 \times 3 + 12 \times ( - 2) - 30 \times 3 \times ( - 2) = \\ = 60 - 24 + 180 = \boxed{216}[/tex]