Odpowiedź :
Odpowiedź:
E = Ep÷g×h = 1÷10×10 = 1÷100 = 0,01kg = 10g
[tex]Dane:\\E_{p} = 1 \ J\\h = 10 \ m\\g = 10\frac{N}{kg}\\Szukane:\\m = ?\\\\Rozwiazanie\\\\E_{p} = mgh \ \ /:gh\\\\m = \frac{E_{p}}{gh}\\\\m = \frac{1 \ J}{10\frac{N}{kg}\cdot10 \ m} =\frac{1 \ N\cdot m}{100\frac{N}{kg}\cdot m}\\\\\boxed{m = 0,01 \ kg =1 \ dag}[/tex]