[tex]Dane:\\m = 80 \ kg\\v = 18\frac{km}{h} = 18:3,6\frac{m}{s} = 5\frac{m}{s}\\r = 2 \ m\\Szukane:\\F_{od} = ?\\\\Rozwiazanie\\\\F_{od}=F_{d} = \frac{mv^{2}}{r}\\\\F_{od} = \frac{80 \ kg\cdot(5\frac{m}{s})^{2}}{2}\\\\\boxed{F_{od} = 1000 \ N = 1 \ kN}\\\\1 \ kN = 1000 \ N)[/tex]
