k]
[tex]2\frac{3}{8}+1\frac{1}{6}=2\frac{3\cdot3}{8\cdot3}+1\frac{1\cdot4}{6\cdot4}=2\frac{9}{24}+1\frac{4}{24}=3\frac{13}{24}\\[/tex]
l]
[tex]4\frac{1}{2}+2\frac{3}{5}=4\frac{1\cdot5}{2\cdot5}+2\frac{3\cdot2}{5\cdot2}=4\frac{5}{10}+2\frac{6}{10}=6\frac{11}{10}=7\frac{1}{10}\\[/tex]
o]
[tex]3\frac{1}{15}-1\frac{1}{10}=3\frac{1\cdot2}{15\cdot2}-1\frac{1\cdot3}{10\cdot3}=3\frac{2}{30}-1\frac{3}{30}=2\frac{32}{30}-1\frac{3}{30}=1\frac{29}{30}\\[/tex]
p]
[tex]5\frac{5}{13}-3\frac{1}{2}=5\frac{5\cdot2}{13\cdot2}-3\frac{1\cdot13}{2\cdot13}=5\frac{10}{26}-3\frac{13}{26}=4\frac{36}{26}-3\frac{13}{26}=1\frac{23}{26}\\[/tex]
