Wzór
[tex]V = \frac{Pp \times H}{3}[/tex]
Dane
[tex]H = 7m[/tex]
Obliczmy pole
[tex] \frac{ {a}^{2} \sqrt{3} }{4} [/tex]
[tex] \frac{ {6}^{2} \sqrt{3} }{4} = \frac{36 \sqrt{3} }{4} = \boxed{9 \sqrt{3} {m}^{2} }[/tex]
Zatem objętość
[tex]V = \frac{ \not9 \bold{ _3}\sqrt{3} \times 7}{ \not3 \bold{_1} } = \boxed{ \boxed{21 \sqrt{3} {m}^{3} }}[/tex]
