Odpowiedź :
[tex]a)\\\frac{1}{2}x=10/:\frac{1}{2} \\x=20[/tex]
[tex]b)\\5x-3=2x+4/+3\\5x=2x+7\\2x+7=5x/-2x\\3x=7/:3\\x=2\frac{1}{3}[/tex]
[tex]c)\\\frac{1}{2}(6x+4)=15\\3x+2=15/-2\\3x=13/:3\\x=4\frac{1}{3}[/tex]
[tex]d)\\\frac{1}{4}x+12=\frac{1}{2}x+3/*4\\x+48=2x+12\\2x+12=x+48/-12\\2x=x+36\\x+36=2x/-x\\x=36[/tex]
[tex]a)\\\frac{1}{2}x = 10 \ \ /\cdot2\\\\\boxed{x = 20}[/tex]
[tex]b)\\2x+4 = 5x-3\\\\2x-5x = -3-4\\\\-3x=-7 \ \ /:(-3)\\\\\boxed{x = \frac{7}{3} = 2\frac{1}{3}}[/tex]
[tex]c)\\\frac{1}{2}(6x+4) = 15 \ \ /\cdot2\\\\6x+4 = 30\\\\6x = 30-4\\\\6x = 26 \ \ /:2\\\\3x = 13 \ \ /:3\\\\\boxed{x = 4\frac{1}{3}}[/tex]
[tex]d)\\\frac{1}{4}x + 12 = \frac{1}{2}x + 3 \ \ /\cdot4\\\\x +48 = 2x+12\\\\x-2x = 12-48\\\\-x = -36 \ \ /:(-1)\\\\\boxed{x = 36}[/tex]