[tex](3\frac{3}{8})^{-\frac{2}{3}}+25^{\frac{1}{2}}*81^{-\frac{1}{2}}=\frac{1}{(3\frac{3}{8})^{\frac{2}{3}}}+(5^{2})^{\frac{1}{2}}*\frac{1}{81^{\frac{1}{2}}}=\frac{1}{\sqrt[3]{(3\frac{3}{8})^{2}}}+5*\frac{1}{81^{\frac{1}{2}}}=\frac{\sqrt[3]{3\frac{3}{8}}}{\frac{27}{8}}+\frac{5}{81^{\frac{1}{2}}}=\frac{\sqrt[3]{\frac{27}{8}}}{\frac{27}{8}}+\frac{5}{(3^{4})^{\frac{1}{2}}}=\frac{\frac{3}{2}}{\frac{27}{8}}+\frac{5}{3^{2}}=\frac{4}{9}+\frac{5}{9}=1[/tex]
[tex]8^{2-\sqrt{5}}:(\frac{1}{2})^{3\sqrt{5}}=(2^{3})^{2-\sqrt{5}}:(2^{-1})^{3\sqrt{5}}=2^{6-3\sqrt{5}}:2^{-3\sqrt{5}}=2^{6}=64[/tex]
