Pierwsze działanie:
[tex]\frac{a+b}{a-b}=\frac{4+9}{4-9}=\frac{13}{-5}=-2\frac{3}{5}[/tex]
- dla a = 3/4 oraz b = -1/4
[tex]\frac{a+b}{a-b}=\frac{\frac{3}{4}+(-\frac{1}{4})}{\frac{3}{4}-(-\frac{1}{4})}=\frac{\frac{3}{4}-\frac{1}{4}}{\frac{3}{4}+\frac{1}{4}}=\frac{\frac{2}{4}}{\frac{4}{4}}=\frac{\frac{1}{2}}{1}=\frac{1}{2}\\[/tex]
Drugie działanie:
[tex]\frac{2\cdot a+1}{3\cdot b+2}=\frac{2\cdot2+1}{3\cdot5+2}=\frac{4+1}{15+2}=\frac{5}{17}\\[/tex]
[tex]\frac{2\cdot a+1}{3\cdot b+2}=\frac{2\cdot0,6+1}{3\cdot0,2+2}=\frac{1,2+1}{0,6+2}=\frac{2,2}{2,6}=\frac{22}{26}=\frac{11}{13}\\[/tex]
Trzecie działanie:
[tex]a^2-b^2=9^2-10^2=81-100=-19\\[/tex]
- dla a = 3/4 oraz b = 1 i 1/2
[tex](\frac{3}{4})^2-(1\frac{1}{2})^2=\frac{3^2}{4^2}-(\frac{3}{2})^2=\frac{9}{16}-\frac{9}{4}=\frac{9}{16}-\frac{36}{16}=-\frac{27}{16}=-1\frac{11}{16}\\[/tex]
