[tex]V = Pp \times H[/tex]
[tex]Pp = 4 \times 4 = 16 {cm}^{2} [/tex]
[tex] {4}^{2} + {h}^{2} = {12}^{2} \\ 16 + {h}^{2} = 144 \\ {h}^{2} = 128 \\ h = \sqrt{128} = \sqrt{64 \times 2} = 8 \sqrt{2} cm[/tex]
Zatem objętość
[tex]V = 16 {cm}^{2} \times 8 \sqrt{2} cm = 128 \sqrt{2} {cm}^{3} [/tex]
Pole powierzchni całkowitej
[tex]2 \times Pp + 4 \times Psb[/tex]
[tex]2 \times 16 {cm}^{2} + 4 \times (4 \times 8 \sqrt{2} ) = 32 {cm}^{2} + 4 \times 32 \sqrt{2} {cm}^{2} = \\ = \boxed {32 {cm}^{2} + 128 \sqrt{2} {cm}^{2}}[/tex]
