Odpowiedź:
a)
[tex]\frac{2x+3}{5} = \frac{2-x}{3} - x \\\frac{2x+3}{5} = \frac{2-x}{3} - \frac{3x}{3} \\ \frac{2x+3}{5} = \frac{2-4x}{3} \\6x +9 = 10 - 20x\\26x = 1 \\x = \frac{1}{26}[/tex]
b)
[tex]\frac{x+1}{2} - \frac{x-1}{3} = \frac{1}{4} \\\frac{3x+3}{6} - \frac{2x-2}{6} = \frac{1}{4} \\\frac{x+5}{6} = \frac{1}{4} \\4x +20 = 6\\4x = -14\\x= - \frac{7}{2}[/tex]
c)
[tex]\frac{4x+7}{2} - \frac{5x-1}{6} = x+5|*6\\12x + 21 -5x +1 = 6x +30\\x = 8[/tex]
d)
[tex]\frac{x+5}{4} - \frac{2x+1}{8} = \frac{1}{2} (2-x)|*8\\2x +10 -2x -1 = 8 -4x \\4x = -1\\x = - \frac{1}{4}[/tex]
