a)
[tex]-24*\sqrt{5\frac{1}{16}}+12*\sqrt[3]{3\frac{3}{8}}-15*\sqrt{2\frac{14}{25}}=-24*\sqrt{\frac{81}{16}}+12*\sqrt[3]{\frac{27}{8}}-15*\sqrt{\frac{64}{25}}=\\=-24*\frac{9}{4}+12*\frac{3}{2}-15*\frac{8}{5}=-6*9+6*3-3*8=-54+18-24=-60[/tex]
b)
[tex]9*\sqrt[3]{\frac{8}{27}}-20*\sqrt{1\frac{9}{16}}+4:\sqrt[3]{\frac{64}{125}}=9*\frac{2}{3}-20*\sqrt{\frac{25}{16}}+4:\frac{4}{5}=3*2-20*\frac{5}{4}+4*\frac{5}{4}=\\=6-5*5+5=6-25+5=-14[/tex]
c)
[tex]\left(-\frac{1}{2}\right)^3*\sqrt{7\frac{1}{9}}-\sqrt[3]{4\frac{17}{27}}*(-1,8)^2-\frac{2^2}{15}=\left(-\frac{1}{8}\right)*\sqrt{\frac{64}{9}}-\sqrt[3]{\frac{125}{27}}*(-\frac{18}{10})^2-\frac{4}{15}=\\=-\frac{1}{8}*\frac{8}{3}-\frac{5}{3}*(-\frac{9}{5})^2-\frac{4}{15}=-\frac{1}{3}-\frac{5}{3}*\frac{81}{25}-\frac{4}{15}=-\frac{1}{3}-\frac{27}{5}-\frac{4}{15}=\\=-\frac{5}{15}-5\frac{6}{15}-\frac{4}{15}=-5\frac{15}{15}=-6[/tex]
d)
[tex]\sqrt{15*\sqrt{45*\sqrt{25}}}-\sqrt[3]{27*\sqrt[3]{256*\sqrt[3]{8}}}=\sqrt{15*\sqrt{45*5}}-\sqrt[3]{27*\sqrt[3]{256*2}}=\\=\sqrt{15*\sqrt{225}}-\sqrt[3]{27*\sqrt[3]{512}}=\sqrt{15*15}-\sqrt[3]{27*8}=\sqrt{225}-\sqrt[3]{216}=15-6=9[/tex]
