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[tex]5 - 2(x + 2) = 9 \\ 4(x - 2) - 2(x - 4) = 5(x + 1) - 3x \\ - \frac{5}{11} (y - 4) = \frac{5}{11} \\ \frac{1}{2} (y + \frac{3}{4} ) + \frac{1}{4} (2y - \frac{1}{2} ) = y + \frac{1}{4} \\ 3.4x + 0.2 = 0.2 + 3.4x[/tex]
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Odpowiedź :

Jvc1nk4viz

1.

[tex]5 - 2(x + 2) = 9 \\ 5 - 2x - 4 = 9 \\ 5 - 4 - 2x = 9 \\ 1 - 2x = 9 \\ - 2x = 9 - 1 \\ - 2x = 8 \\ x = 8 \div ( - 2) \\ x = - 4[/tex]

2.

[tex]4(x - 2) - 2(x - 4) = 5(x + 1) - 3 \\ 4x - 8 - 2x + 8 = 5x + 5 - 3 \\ 4x - 2x - 8 + 8 = 5x + 5 - 3 \\ 2x = 5x + 5 - 3 \\ 2x - 5x = 5 - 3 \\ - 3x = 2 \\ x = 2 \div ( - 3) \\ x = - \frac{2}{3} [/tex]

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