Matematyka z plusem 7 strona 248
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Matematyka Z Plusem 7 Strona 248 Daje Naj class=

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7.

[tex]a) \ \sqrt{81}+5 = \sqrt{9^{2}}+5 = 9+5 = 14\\\\b) \ \sqrt[3]{1000}-100 = \sqrt[3]{10^{3}}-100 = 10-100=-90\\\\c) \ 4\sqrt{\frac{1}{121}} = 4\sqrt{\frac{1}{11^{2}}} = 4\cdot\frac{1}{11} = \frac{4}{11}\\\\d) \ \frac{\sqrt[3]{-27}}{18} = \frac{-3}{18} = -\frac{1}{6}\\\\e) \ 2\sqrt[3]{125}-3 = 2\sqrt[3]{5^{3}}-3 = 2\cdot5-3 = 10-3 = 7\\\\f) \ \frac{6}{\sqrt{144}}+1 = \frac{6}{12}+1 = \frac{1}{2}+1 = 1\frac{1}{2}[/tex]

[tex]g) \ \frac{3\sqrt[3]{-8}}{4}-5 = \frac{3\cdot(-2)}{4}-5 = \frac{-6}{4}-5 = -\frac{3}{2}-5 = -1\frac{1}{2}-5 = -6\frac{1}{2}\\\\h) \ \sqrt{16}+\sqrt[3]{125}=4 +5 = 9\\\\i) \ \sqrt{169} + \sqrt{36}-\sqrt{49} =13+6-7 =19-7 = 12\\\\j) \ \sqrt[3]{1000}\cdot\sqrt{9} = 10\cdot3 = 30\\\\k) \ \sqrt{900}:\sqrt[3]{27} = 30:3 = 10\\\\l) \ 3\sqrt{36}=5\sqrt[3]{-64} = 3\cdot6 - 5\cdot(-4) = 18+20 = 38[/tex]

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