Odpowiedź:
[tex]\dfrac{2\sqrt{27}+\sqrt{75}}{\sqrt{12}}=\dfrac{2\sqrt{9\cdot3}+\sqrt{25\cdot3}}{\sqrt{4\cdot3}}=\dfrac{2\cdot3\sqrt{3}+5\sqrt{3}}{2\sqrt{3}}=\dfrac{6\sqrt{3}+5\sqrt{3}}{2\sqrt{3}}=\dfrac{11\sqrt{3}}{2\sqrt{3}}=\\\\\\=\dfrac{11}{2}=5\dfrac{1}{2}[/tex]
