Odpowiedź:
a)
[tex] {10p}^{2} + 4pq + 15pq + {6q}^{2} = {10p}^{2} + 19pq + {6q}^{2} [/tex]
b)
[tex] {3a}^{2} - 12ab + 2ab - {8b}^{2} = {3a}^{2} - 10ab { - 8b}^{2} [/tex]
c)
[tex] {6x}^{2} - 4xy - 9xy + {6y}^{2} = {6x}^{2} - 13xy + {6y}^{2} [/tex]
d)
[tex] {10a}^{2} b + {15a}^{3} - {2b}^{2} - 3ab [/tex]
