Odpowiedź:
[tex]\huge\boxed{\boxed{m_{H_2SO_4}=98 \ u}}[/tex]
[tex]\huge\boxed{\boxed{m_{3K_2O}=282 \ u}}[/tex]
[tex]\huge\boxed{\boxed{m_{3O_2}=96 \ u}}[/tex]
[tex]\huge\boxed{\boxed{m_{HNO_2}=47 \ u}}[/tex]
Wyjaśnienie:
Obliczenia dla H₂SO₄
[tex]m_H=1 \ u\\\\m_S=32 \ u\\\\m_O=16 \ u\\\\m_{H_2SO_4}=2\cdot1 \ u+32 \ u+4\cdot16 \ u=2 \ u+32 \ u+64 \ u=98 \ u[/tex]
Obliczenia dla 3K₂O
[tex]m_K=39 \ u\\\\m_O=16 \ u\\\\m_{3K_2O}=3\cdot(2\cdot39 \ u+16 \ u)=3\cdot(78 \ u+16 \ u)=3\cdot94 \ u=282 \ u[/tex]
Obliczenia dla 3O₂
[tex]m_O=16 \ u\\\\m_{3O_2}=3\cdot(16 \ u\cdot2)=3\cdot32 \ u=96 \ u[/tex]
Obliczenia dla HNO₂
[tex]m_H=1 \ u\\\\m_N=14 \ u\\\\m_O=16 \ u\\\\m_{HNO_2}=1 \ u+14 \ u+2\cdot16 \ u=15 \ u+32 \ u=47 \ u[/tex]
