Odpowiedź:
Punkt e)
[tex]y=x^2\sqrt{2} -4x+\sqrt{2}=\sqrt{2}(x^2-\frac{4}{\sqrt{2}}x+1)=\sqrt{2}[x^2-2\sqrt{2}x+(\sqrt{2})^2-1]=\\=\sqrt{2}[(x-\sqrt{2})^2-1]=\sqrt{2}(x-\sqrt{2})^2-\sqrt{2}[/tex]
Punkt f)
[tex]y=-x^2\sqrt{3}-2x-\sqrt{3}=-\sqrt{3}(x^2+\frac{2}{\sqrt{3}}x-1)=-\sqrt{3}[x^2+\frac{2\sqrt{3}}{3}x+(\frac{\sqrt{3}}{3})^2-(\frac{\sqrt{3}}{3})^2-1]\\ =-\sqrt{3}[(x+\frac{\sqrt{3}}{3})^2-\frac{4}{3}]=-\sqrt{3}(x+\frac{\sqrt{3}}{3})^2+\frac{4\sqrt{3}}{3}[/tex]
