[tex]y = ax + b \ - \ postac \ kierunkowa\\\\\\y = -3x+2\\\\a_1 = -3\\\\a_1\cdot a_2 = -1 \ - \ warunek \ prostopadlosci \ prostych\\\\a_2 = \frac{1}{3}\\\\\underline{y = \frac{1}{3}x + b}\\\\A = (-6,7) \ \ \rightarrow \ \ x = -6, \ y = 7\\\\podstawiam \ x \ i \ y \ do \ wzoru \ powyzej\\\\7 = \frac{1}{3}\cdot(-6)+b\\\\7 = -2 + b\\\\\underline{b = 9}\\\\\boxed{y = \frac{1}{3}x+9} \ - \ rownanie \ prostej \ prostopadlej \ do \ danej[/tex]
