Odpowiedź:
a)
[tex]\frac{x-6}{x-5} =\frac{5}{2}\\ 2x -12 = 5x - 25\\3x = 13 \\x = \frac{13}{3}[/tex]
b)
[tex]x(4x-3)(x^2-5)=0[/tex]
[tex]x =0; x =\frac{3}{4} ; x = \sqrt{5} ; x = -\sqrt{5}[/tex]
c)
[tex]\frac{2-x}{-5} = \frac{3}{x} \\-x^2 +2x = -15 \\-x^2 +2x + 15 = 0[/tex]
Δ = 4 +60 = 64
[tex]x_{1} = \frac{-2-8}{-2} = 5\\x_{2} = \frac{-2+8}{-2} = -3\\[/tex]
