Pole podstawy
[tex] \frac{ {a}^{2} \sqrt{3} }{4} = \frac{ {6}^{2} \sqrt{3} }{4} = \frac{36 \sqrt{3} }{4} = 9 \sqrt{3} {cm}^{2} [/tex]
Objętość ostrosłupa
[tex] \frac{Pp \times H}{3} = \frac{9 \sqrt{3} \times 10}{3} = 3 \sqrt{3} \times 10 = 30 \sqrt{3} {cm}^{3} [/tex]
