[tex]podstawa\ to\ trojkat\ rownoboczny \ o\ krawedzi:\ a=4\ cm\\\\wysokosc\ ostroslupa:\ \ H=6\ cm\\\\objetosc\ ostrosluoa:\\\\V=\frac{1}{3}P_ {p}*H\\\\pole\ podstawy:\\\\P_{p}=\frac{a^2\sqrt{3}}{4}\\\\P_{p}=\frac{4^2\sqrt{3}}{4}=\frac{\not{16}^4\sqrt{3}}{\not{4}^1}=4\sqrt{3}\ cm^3\\\\V=\frac{1}{\not{3}^1}*4\sqrt{3}*\not{6}^2=8\sqrt{3}\ cm^3\\\\odp.\ Objetosc\ tego\ ostroslupa\ wynosi\ 8\sqrt{3}\ cm^3.[/tex]
