Odpowiedź:
[tex]a) \frac{x}{3} + 1 = \frac{5}{6} + \frac{x}{2} = 2x + 6 = 5 + 3x = 2x - 3x = 5-6 = -x = -1, wiec[/tex] [tex]x=1[/tex]
[tex]b) \frac{2x-3}{4} = \frac{1}{2}+x = 2x - 3 = 2 + 4x = 2x - 4x = 2+3 = -2x=5, wiec[/tex] [tex]x=-\frac{5}{2}[/tex]
[tex]c) \frac{x+2}{9} +\frac{x-1}{3}=1 = x+2+3(x-1)=9 = x+2+3x-3=9=4x-1=9=4x=9+1=4x=10 ,wiec, x=\frac{5}{2}[/tex]
[tex]d) \frac{2x+3}{5} =\frac{2-x}{3} +x = 3(2x+3)=5(2-x)+15x=6x+9=10-5x+15x=6x+9=10+10x = 6x-10x=10-9=-4x=1, wiec,x=-\frac{1}{4}[/tex]
[tex]e) \frac{3x-5}{2}-\frac{5x-1}{10} =0 = 5(3x-5)-(5x-1)=0=15x-25-5x+1=0=10x-24=0=10x=24, wiec,x=\frac{12}{5}[/tex]
[tex]f) \frac{x}{2}=\frac{2}{5}(4-x)-4=\frac{x}{2}=-\frac{12}{5}-\frac{2}{5}x=5x=-24-4x=5x+4x=-24=9x=-24, wiec,x=-\frac{8}{3}[/tex]
[tex]g) \frac{2x-1}{5}-\frac{x-2}{2}=0,7x=\frac{2x-1}{5}-\frac{x-2}{2}=\frac{7}{10}x=2(2x-1)-5(x-2)=7x=4x-2-5x+10=7x=-x+8=7x=-x-7x=-8=-8x=-8, wiec,x=1[/tex]
[tex]h) 2x-\frac{3x+5}{4}=-\frac{1}{4}x-1=8x-(3x-5)=-x-4=8x-3x+5=-x-4=5x+5=-x-4=5x+x=-4-5=6x=-9, wiec,x=-\frac{3}{2}[/tex]
Podsumowując, wyniki to:
a) x=1
b) x=-5/2
c) x=5/2
d) x=-1/4
e) x=12/5
f) x=-8/3
g) x=1
h) x=-3/2
Pozdrawiam i życzę powodzenia <3
