Odpowiedź:
[tex](4+\sqrt{2})(4-\sqrt{2}) = 4^{2}-\sqrt{2}^{2} = 16-2 = 14\\\\(3-2\sqrt{5})(3+2\sqrt{5}) = 3^{2}-(2\sqrt{5})^{2} = 9-2^{2}\cdot\sqrt{5}^{2} = 9-4\cdot5 = 9-20 = -11\\\\(3\sqrt{3}-\sqrt{2})(3\sqrt{2}+\sqrt{2}) = (3\sqrt{3})^{2}-\sqrt{2}^{2} = 3^{2}\cdot\sqrt{3}^{2} -2 = 9\cdot3-2 = 27-2 = 25[/tex]
Szczegółowe wyjaśnienie:
[tex](a+b)(a-b) = a^{2}-b^{2}[/tex]
