[tex]Dane:\\m =1,5 \ t = 1 \ 500 \ kg\\W = 30 \ kJ = 30 \ 000 \ J\\g = 10\frac{N}{kg}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\W = E_{p} = mgh\\\\W = mgh \ \ /:mg\\\\h = \frac{W}{mg}\\\\h = \frac{30000 \ J}{1500 \ kg\cdot10\frac{N}{kg}}=\frac{30000 \ N\cdot m}{1500 \ kg\cdot10\frac{N}{kg}}\\\\\boxed{h = 2 \ m}[/tex]
Odp. Podnośnik uniesie ten samochód na wysokosć 2 m.
