A
[tex]4 \frac{3}{7} + 1 \frac{1}{5} = 4 \frac{15}{35} + 1 \frac{7}{35} = 5 \frac{22}{35} [/tex]
B
[tex]5 \frac{2}{3} - 2 \frac{1}{4} = 5 \frac{8}{12} - 2 \frac{3}{12} = 3 \frac{5}{12} [/tex]
C
[tex]4 \frac{3}{10} - 2 \frac{1}{5} = 4 \frac{3}{10} - \frac{2}{10} = 2 \frac{1}{10} [/tex]
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