Odpowiedź:
[tex]a)\ \ (2-x)^3=2^3-3\cdot2^2\cdot x+3\cdot2x^2-x^3=8-3\cdot4x+6x^2-x^3=8-12x+6x^2-x^3\\\\\\b)\ \ (3x+4)^3=(3x)^3+3\cdot(3x)^2\cdot4+3\cdot3x\cdot4^2+4^3=27x^3+3\cdot9x^2\cdot4+9x\cdot16+64=\\\\=27x^3+108x^2+144x+64\\\\\\c)\ \ (x+4)^2=x^2+2x\cdot4+4^2=x^2+8x+16\\\\\\d)\ \ x^3+5^3=(x+5)(x^2-x\cdot5+5^2)=(x+5)(x^2-5x+25)[/tex]
[tex]Zastosowane\ \ wzory\\\\(a-b)^3=a^3-3a^2b+3ab^2-b^3\\\\(a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\(a+b)^2=a^2+2ab+b^2\\\\a^3+b^3=(a+b)(a^2-ab+b^2)[/tex]
