Odpowiedź :
[tex]\frac{3-5x}{2} = 1 - \frac{x-2}{3} | *6\\\\3(3-5x) = 6 - 2(x-2)\\\\9 - 15x = 6 - 2x + 4\\\\-15x + 2x = 6 + 4 - 9\\\\-13x = 1 |:(-13)\\\\x = -\frac{1}{13}[/tex]
[tex]\frac{3-5x}{2} = 1 - \frac{x-2}{3} | *6\\\\3(3-5x) = 6 - 2(x-2)\\\\9 - 15x = 6 - 2x + 4\\\\-15x + 2x = 6 + 4 - 9\\\\-13x = 1 |:(-13)\\\\x = -\frac{1}{13}[/tex]