Odpowiedź :
[tex] \frac{ - 3.9 {x }^{2} + 2x - 0.6 }{ - 3} = \frac{13}{10} {x}^{2} - \frac{2}{3} x + \frac{1}{5} [/tex]
[tex] \frac{ - 3.9 {x}^{2} + 2x - 0.6}{ - 3} = \frac{13}{10} {x}^{2} - \frac{2}{3} x + \frac{1}{5} [/tex]
[tex] \frac{ - 3.9 {x }^{2} + 2x - 0.6 }{ - 3} = \frac{13}{10} {x}^{2} - \frac{2}{3} x + \frac{1}{5} [/tex]
[tex] \frac{ - 3.9 {x}^{2} + 2x - 0.6}{ - 3} = \frac{13}{10} {x}^{2} - \frac{2}{3} x + \frac{1}{5} [/tex]