[tex]wysokosc\ ostroslupa:\ H=5\ cm\\\\wysokosc\ podstawy:\ h=18\ cm\\\\krawedz\ podstawy:\ a=?\\\\wzor\ na\ wysokosc\ w\ trojkacie\ ro wnobocznym:\\\\h=\frac{a\sqrt{3}}{2} \\\\\frac{a\sqrt{3}}{2}=18\ \ | *\frac{2 } {\sqrt{3}}\\\\a=\frac{36}{\sqrt{3}} *\frac{\sqrt{3}}{\sqrt{3}}=\frac{36\sqrt{3}}{3}=12\sqrt{3}\ cm[/tex]
[tex]objetosc\ ostroslupa:\\\\V=\frac{1}{3} P_{p}*H\\\\pole\ podstawy:\\\\P_{p}=\frac{a^2\sqrt{3}}{4}\\\\P_{p}=\frac{(12\sqrt{3})^2*\sqrt{3}}{4}=\frac{\not{144}^{16}*3\sqrt{3}}{\not{4}^1 }=48\sqrt{3}\ cm^2\\\\V=\frac{1}{\not{3}^1}*\not{48}^{16}\sqrt{3}*5=80\sqrt{3}\ cm^3\\\\Odp.\ Obejetosc\ tego\ ostroslupa\ wynosi\ 80\sqrt{3}\ cm^3.[/tex]
