Odpowiedź:
Zadanie 13.
n = 90
t = 40s
T = [tex]\frac{t}{n}[/tex] = [tex]\frac{40}{90}[/tex] = [tex]\frac{4}{9}[/tex] s
f = [tex]\frac{1}{T}[/tex]
f = [tex]\frac{1}{\frac{4}{9}}[/tex]
f = [tex]\frac{9}{4}[/tex] = 2[tex]\frac{1}{4}[/tex] Hz
Zadanie 14.
v = s/t
0,8 m/s = s / 1s
s = 0,8m
s = 80 cm
Zadanie 15.
T = 16s
A = 15cm
f = [tex]\frac{1}{T}[/tex] = [tex]\frac{1}{16}[/tex] Hz
Ciało będzie w położeniu maksymalnego wychylenia
Zadanie 16.
T = 8s
λ = 120cm
f = ?
v = ?
f = [tex]\frac{1}{T}[/tex] = [tex]\frac{1}{8}[/tex] Hz
v = λf
v = 120 · [tex]\frac{1}{8}[/tex] = 15 cm/s = 0,15 m/s
Zadanie 17.
λ = [tex]\frac{v}{f}[/tex]
v = 300 000 km/s
f = 144,1 MHz
λ = [tex]\frac{300 000 km/s}{144,1MHz}[/tex]
λ = [tex]\frac{300000km/s}{144100000Hz}[/tex]
λ = [tex]\frac{3 km/s}{1441 Hz}[/tex]
λ ≈ 0,002 km
λ = 2m
Wyjaśnienie:
