[tex]a)\\\\ 3\frac{3}{4}- 1\frac{1}{4} :\frac{5}{6}+1\frac{3}{4}=3\frac{3}{4}- \frac{\not{5}^1}{4} *\frac{6}{\not{5}^1}+1\frac{3}{4}= 4\frac{6}{4}- \frac{6}{4} =4 \\\\\frac{4}{35} \\\\odp.\ Liczba\ 4\ stanowi \ \frac{4}{35}\ liczby\ 35.[/tex]
[tex]b)\\\\ ( 2\frac{2}{3}+ \frac{1}{4}*1\frac{7}{9}): 3\frac{1}{9}=( 2\frac{2}{3}+ \frac{1}{\not{4}^1}* \frac{\not{16}^4}{9}): \frac{28}{9} =( 2\frac{6}{9}+ \frac{4}{9})* \frac{9}{28}= 2\frac{10}{9}*\frac{9}{28} =\\\\=\frac{\not{28}^1}{\not{9}^1}*\frac{\not{9}^1}{\not{28}^1}=1\\\\odp.\ Liczba\ 1\ stanowi \ \frac{1}{35}\ liczby\ 35.[/tex]
