[tex]a)\\\\4\frac{1}{2}:6 +3\frac{2}{3}= \frac{\not{9}^3}{2}*\frac{1}{\not{6}^2}+3\frac{2}{3}=\frac{3}{4}+3\frac{2}{3}=\frac{9}{12}+3\frac{8}{12} =3\frac{17}{12}=4\frac{5}{12}[/tex]
[tex]b)\\\\(5\frac{1}{3}-2\frac{2}{5} ):2=(5\frac{5}{15}-2\frac{6}{15} )*\frac{1}{2}=(4\frac{20}{15}-2\frac{6}{15} )*\frac{1}{2}= 2\frac{14}{15}*\frac{1}{2}=\frac{\not{44}^{22}}{15}*\frac{1}{\not{2}^1}=\\\\=\frac{22}{15}=1\frac{7}{15}[/tex]
[tex]c)\\\\ (5\frac{1}{2}-3\frac{1}{4}):7= (5\frac{2}{4}-3\frac{1}{4})*\frac{1}{7}=2\frac{1}{4}*\frac{1}{7}=\frac{9}{4}*\frac{1}{7}=\frac{9}{28}[/tex]
