5.
[tex]Dane:\\V = 5 \ dm^{3}\\d = 1,52\frac{kg}{dm^{3}}\\Szukane:\\m = ?[/tex]
Rozwiązanie
Korzystamy ze wzoru na gęstość substancji:
[tex]d = \frac{m}{V} \ \ /\cdot V\\\\m = d\cdot V\\\\m = 1,52\frac{kg}{m^{3}}\cdot5 \ dm^{3}\\\\\boxed{m = 7,6 \ kg}[/tex]
6.
[tex]Dane:\\d_1 = d_2 = d_3 = d\\m_1 = 450 \ g\\V_1 = 20 \ cm^{3}\\V_2 = 80 \ cm^{3}\\V_3 = 140 \ cm^{3}\\Szukane:\\m_2,m_3 = ?[/tex]
Rozwiazanie
[tex]d = \frac{m_1}{V_1}=\frac{450 \ g}{20 \ cm^{3}} = 22,5\frac{g}{cm^{3}}\\\\m = d\cdot V\\\\m_2 = d\cdot V_2\\\\m_2 = 22,5\frac{g}{cm^{3}}\cdot80 \ cm^{3} =\boxed{ 1 \ 800 \ g = 1,8 \ kg}\\\\m_3 = d\cdot V_3\\\\m_3 = 22,5\frac{g}{cm^{3}}\cdot140 \ cm^{3} =\boxed{ 3 \ 150 \ g = 3,15 \ kg}[/tex]
